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CreateDefaultSubobject FName argument curiosity

How come the FName argument to CreateDefaultSubobject can accept a direct TEXT("") without having to wrap it in an FName() constructor? What is the C++ mechanism by which automatic conversion to an FName happens?

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asked Dec 07 '14 at 08:13 AM in C++ Programming

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Hi, This is standard c++ stuff.

The constructor is called implicitly with a TEXT("") argument. You can have a look at NameTypes.h in the Engine and see the implementation of FName.

these two constructors:

 FName( const WIDECHAR*  Name, EFindName FindType=FNAME_Add, bool bUnused=true );
 FName( const ANSICHAR* Name, EFindName FindType=FNAME_Add, bool bUnused=true );

Can be implicitly called (think about std::String, it can also be implicitly called passing a char* argument).

So, if the compiler type checking expects a FName and can call a implicit constructor it will do so.

In addition, you can forbid implicit constructor calling by flagging the constructor with "explicit" keyword, then you will have to call explictly the constructor.

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answered Dec 07 '14 at 09:48 AM

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avatar image dekrat Dec 09 '14 at 02:20 AM

Of course! I don't know why it seemed so mysterious to me. Thanks for clearing it up.

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