x

Search in
Sort by:

Question Status:

Search help

  • Simple searches use one or more words. Separate the words with spaces (cat dog) to search cat,dog or both. Separate the words with plus signs (cat +dog) to search for items that may contain cat but must contain dog.
  • You can further refine your search on the search results page, where you can search by keywords, author, topic. These can be combined with each other. Examples
    • cat dog --matches anything with cat,dog or both
    • cat +dog --searches for cat +dog where dog is a mandatory term
    • cat -dog -- searches for cat excluding any result containing dog
    • [cats] —will restrict your search to results with topic named "cats"
    • [cats] [dogs] —will restrict your search to results with both topics, "cats", and "dogs"

Office Holiday

Epic Games' offices will be on holiday from June 22nd to July 7th. During this period support will be limited. Our offices will reopen on Monday, July 8th. 

checking which collision box on same actor

Curious how I'm supposed to tell what collision box is being hit when multiple collision boxes are being used on 1 actor.

I saw if (CollisionComp->IsOverlappingActor(OtherActor)) but that doesn't seem to work for onhit. / blocking, is there a way to check which box is being hit that is not using overlapping ?

Product Version: UE 4.8
Tags:
more ▼

asked Feb 20 '16 at 10:35 PM in C++ Programming

avatar image

spazchicken
447 35 20 53

(comments are locked)
10|2000 characters needed characters left
Viewable by all users

1 answer: sort voted first

Doing the below in the Onhit function works

         UPrimitiveComponent * theComp = Hit.GetComponent();
 
     if (theComp == MyCollisionCompnent)
     {
 
        }


more ▼

answered Mar 12 '16 at 12:46 AM

avatar image

spazchicken
447 35 20 53

(comments are locked)
10|2000 characters needed characters left
Viewable by all users
Your answer
toggle preview:

Up to 5 attachments (including images) can be used with a maximum of 5.2 MB each and 5.2 MB total.

Follow this question

Once you sign in you will be able to subscribe for any updates here

Answers to this question