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Method Calling Method

I was watching the video of accessing member functions through pointers and there is this statement i cant understand

GetOwner()->GetName(); how can a method call a method

Product Version: UE 4.11
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asked Sep 15 '16 at 01:08 PM in C++ Programming

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Anagh
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The method GetOwner() returns a pointer to an object, and then GetName() is called on that object.

You can think of it as:

GetOwner()->GetName();

is the same as:

(GetOwner())->GetName();

which results in:

(A Pointer to the Owner)->GetName();

or

(3 + 5)->GetName();

(8)->GetName();

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answered Sep 15 '16 at 04:03 PM

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staticvoidlol
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avatar image Anagh Sep 15 '16 at 04:38 PM

But I Have Used ->operator to access elements of a Structure Using a Pointer

avatar image NoobsDeSroobs Sep 15 '16 at 06:58 PM

Yes. The -> operator is really two operators in one package.

(*ptr).YourMember

The * dereferences the object and then you access it using the . operator. So the function returns a pointer to MyObject. Then you dereference that pointer to get the object itself like so: (*MyObject). My Object has a member function that you call. (*MyObject).MemberFunction(). Using the function instead of the variable we get (GetMyObject()).MemberFunction(). Replacing the operator and the . operator with the -> operator we get GetMyObject()->MemberFunction()

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