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% is not modulo, wrong description

When you search modul (blueprint), you obtain the funciton "modulo: %", but this function is not modulo, it is the remainder of a division. Rest and modulo are equals ONLY IN POSITIVE NUMBERS

For example -84 mod 360 = 276 -84 % 360 = -84

So no, this is not modulo.

Product Version: UE 4.15
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asked Apr 26 '17 at 12:08 PM in Bug Reports

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avatar image Memnarch Apr 26 '17 at 02:49 PM

% in C++ is called Modulus and returns the remainder of the division.

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2 answers: sort voted first

This is working as intended, as the Engine's modulo node returns the same value as the modulo math function in c++. Different programming languages handle modulo differently. Here is another post that discusses this issue, which you may find helpful:



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answered Apr 26 '17 at 02:41 PM

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Thomas G ♦♦ STAFF
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avatar image Cucharón Apr 28 '17 at 11:03 AM

No, C++ % is not modulo, is, again, remainder of a division. If I go to C++ and I write %, I am writing remainder of a division, not modulo.

And even if the name in C++ were modulo, because you use fmodulo, it is still wrong, because your shortnames says "%" not "fmod".

So at least you could add to the description: Reminder of the division, not mod.

avatar image Benergy Apr 28 '17 at 01:16 PM

Do you have any resource on why modulo is not the remainder of a division? I googled it and couldn't find anything reliable, only things like "depends on the implementation for negative numbers".

avatar image ThompsonN13 Apr 27 '18 at 09:56 PM

i agree with the other replies here in that it works as intended if you have a problem with it not being positive numbers then just use a absolute node.

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Hi, I found this thread while trying to confirm the correct operation for remainders. As far as I know:

1) "Mod" IS the operation for getting the remainder. Has been for at least the last 2+ decades, at least in C++

2) My understanding is that "Modulo" actually refers to the remainder. Wikipedia seems to confirm that as well: https://en.wikipedia.org/wiki/Modulo_operation

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answered Apr 27 '18 at 08:28 PM

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