Search in
Sort by:

Question Status:

Search help

  • Simple searches use one or more words. Separate the words with spaces (cat dog) to search cat,dog or both. Separate the words with plus signs (cat +dog) to search for items that may contain cat but must contain dog.
  • You can further refine your search on the search results page, where you can search by keywords, author, topic. These can be combined with each other. Examples
    • cat dog --matches anything with cat,dog or both
    • cat +dog --searches for cat +dog where dog is a mandatory term
    • cat -dog -- searches for cat excluding any result containing dog
    • [cats] —will restrict your search to results with topic named "cats"
    • [cats] [dogs] —will restrict your search to results with both topics, "cats", and "dogs"

Drunk/curvy AI move path

I have a character that should folliow another actor with deviations to left and right (drunk movement). I have been digging through AI_MoveTo code, but cant seem to grasp the right way of doing it. Can anyone help me with some pointers or tips? What classes should I extend/override?

I dont mind c++ nor blueprints.

Cheers guys!

Product Version: UE 4.16
more ▼

asked Jul 17 '17 at 09:43 PM in C++ Programming

avatar image

44 8 12 18

avatar image iSpam Oct 29 '17 at 06:11 PM

My thought would be to do whatever side of the target's y axis, do a move to the opposite side, and your walkspeed could do something like the closer it gets increase the speed until a certain point then drastically reduce it. You could use a random int so that it isn't the same every time. I think you could handle it with a simple move to location to be honest, but that's because I'm not such a great programmer that I can fiddle with source code.

(comments are locked)
10|2000 characters needed characters left

0 answers: sort voted first
Be the first one to answer this question
toggle preview:

Up to 5 attachments (including images) can be used with a maximum of 5.2 MB each and 5.2 MB total.

Follow this question

Once you sign in you will be able to subscribe for any updates here

Answers to this question